log: Difference between revisions
Jump to navigation
Jump to search
Lou Montana (talk | contribs) m (Text replacement - "\| \[\[.+\]\] \<nowiki\>\=\<\/nowiki\> " to "| ") |
Lou Montana (talk | contribs) m (Text replacement - "\[https?\:\/\/en\.wikipedia\.org\/wiki\/([^ ]+) (.+)\]" to "{{Wikipedia|$1|$2}}") |
||
| Line 17: | Line 17: | ||
|x1= <code>_log = [[log]] 10; // 1</code> | |x1= <code>_log = [[log]] 10; // 1</code> | ||
| [[Math Commands]], | | [[Math Commands]], {{Wikipedia|Logarithm|Logarithm}} | ||
}} | }} | ||
Revision as of 15:55, 30 May 2021
Description
- Description:
- Description needed
- Groups:
- Math
Syntax
- Syntax:
- Syntax needed
- Parameters:
- x: Number
- Return Value:
- Return value needed
Examples
- Example 1:
_log = log 10; // 1
Additional Information
- See also:
- See also needed
Notes
-
Report bugs on the Feedback Tracker and/or discuss them on the Arma Discord or on the Forums.
Only post proven facts here! Add Note
- Posted on 23:14, 16 Jun 2014
- ffur2007slx2_5
-
(A3 1.20) To clarify:
y = 10 ^ x // x = log yPeople use logarithm at the purpose of simplifying multiplication via exponents plus years before.23456*45634 = 1.07039e+009 log 23456 = 4.37025; log 45634 = 4.65929; (log 23456) + (log 45634) = 9.02954 10^((log 23456) + (log 45634)) = 10 ^ 9.02954 // same as 23456*45634As modern usage, for instance, to evaluate another exponent when multiple is known (Which magnitude is 4 times stronger than 8.3 earthquake?)://_Unknown = log x; 8.3 = log y // x = 10 ^_Unknown; y = 10 ^8.3 //x/y = (10 ^_Unknown)/(10 ^8.3) = log 4 // x/y = _Unknown – 8.3 = 0.6 //_result = 8.9 magnitude _result = (log 4) + 8.3