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Revision as of 16:38, 9 August 2014

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Posted on 23:14, 16 Jun 2014
ffur2007slx2_5: (A3 1.20) To clarify: y = 10 ^ x // x = log y People use logarithm at the purpose of simplifying multiplication via exponents plus years before. 23456*45634 = 1.07039e+009 log 23456 = 4.37025; log 45634 = 4.65929; (log 23456) + (log 45634) = 9.02954 10^((log 23456) + (log 45634)) = 10 ^ 9.02954 // same as 23456*45634 As modern usage, for instance, to evaluate another exponent when multiple is known (Which magnitude is 4 times stronger than 8.3 earthquake?): //_Unknown = log x; 8.3 = log y // x = 10 ^_Unknown; y = 10 ^8.3 //x/y = (10 ^_Unknown)/(10 ^8.3) = log 4 // x/y = _Unknown – 8.3 = 0.6 //_result = 8.9 magnitude _result = (log 4) + 8.3

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 ____________________________________________________________________________________________
-|x1= <pre>_log = log 10 ..........Result is 1</pre> |= Example 1
+|x1= <code>_log = [[log]] 10; // 1</code> |= Example 1
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@@ Line 30: / Line 30: @@
 <dt class="note">[[User:ffur2007slx2_5|ffur2007slx2_5]]</dt>
 <dd class="note">
-(ArmA3 1.20) To clarify:
+(A3 1.20) To clarify:
-<code>y = 10 ^ x // x = log y</code>
+<code>y = 10 ^ x // x = [[log]] y</code>
 People use logarithm at the purpose of simplifying multiplication via exponents plus years before.
 <code>23456*45634 = 1.07039e+009
@@ Line 38: / Line 38: @@
 </code>
 As modern usage, for instance, to evaluate another exponent when multiple is known (Which magnitude is 4 times stronger than 8.3 earthquake?):
-<code>//_Unknown = log x; 8.3 = log y
+<code>//_Unknown = [[log]] x; 8.3 = [[log]] y
 // x = 10 ^_Unknown; y = 10 ^8.3
 //x/y = (10 ^_Unknown)/(10 ^8.3) = [[log]] 4