arrayIntersect – Talk

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_fistArray = ["a","b",0,1];<br>
_fistArray = ["a","b",0,1];<br>
_secondArray = [1,"b",0,"a"];<br>
_secondArray = [1,"b",0,"a"];<br>
_areEquivalent = ["a","b",0,1] isEqualTo ([1,"b",0,"a"] arrayIntersect ["a","b",0,1]) // returns true
_areEquivalent = _firstArray isEqualTo (_secondArray arrayIntersect _firstArray) // returns true
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Revision as of 21:15, 11 December 2018

Posted on December 11, 2018 - 18:09 (UTC)
Pierre MGI
useful to compare two arrays with same (single) elements but in different order:
_areEquivalent = _firstArray isEqualTo (_secondArray arrayIntersect _firstArray);
example:
_fistArray = ["a","b",0,1];
_secondArray = [1,"b",0,"a"];
_areEquivalent = _firstArray isEqualTo (_secondArray arrayIntersect _firstArray) // returns true
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