vectorCrossProduct

1.22

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Description

Description:

Cross product of two 3D vectors.
In layman's terms, if you have a polygon (surface) defined by 3 points, you can find a normal to it (just like terrain surfaceNormal). To invert direction of the normal, swap arguments around.

Groups:

Uncategorised

Syntax

Syntax:

vector1 vectorCrossProduct vector2

Parameters:

vector1: [x, y, z] Array

vector2: [x, y, z] Array

Return Value:

Array - vector: [x, y, z]

Examples

Example 1:

_vector = [1,1,1] vectorCrossProduct [2,2,2];

Example 2:

_vectorUp = [0,1,0] vectorCrossProduct [-1,0,0]; //[0,-0,1]

Additional Information

See also:

vectorAddvectorDiffvectorDotProductvectorCosvectorMagnitudevectorMagnitudeSqrvectorMultiplyvectorDistancevectorDistanceSqrvectorDirvectorUpsetVectorDirsetVectorUpsetVectorDirAndUp

Notes

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Notes

Posted on 28 Jun, 2014

ffur2007slx2_5

(ArmA3 1.22)Algorithm: Vector1 = [x1,y1,z1]; Vector2 = [x2,y2,z2]; Result = [(y1 * z2) – (z1 * y2),(z1 * x2) – (x1 * z2),(x1 * y2) – (y1 * x2)]; It is recommended to use vectorCrossProduct instead of BIS_fnc_crossProduct.