vectorFromTo: Difference between revisions

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m (Text replacement - "\|x([0-9])= *<code>([^<]*)<\/code>" to "|x$1= <sqf>$2</sqf>")
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<dd class="note">
<dd class="note">
{{GVI|arma3|1.26}} Algorithm:
{{GVI|arma3|1.26}} Algorithm:
<code>Vector1 = [x1,y1,z1];
<sqf>Vector1 = [x1,y1,z1];
Vector2 = [x2,y2,z2];
Vector2 = [x2,y2,z2];
Result = [
Result = [
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(y1 – y2) / (sqrt ((x1 – x2) ^ 2 + (y1 – y2) ^ 2 + (z1 – z2) ^ 2)),  
(y1 – y2) / (sqrt ((x1 – x2) ^ 2 + (y1 – y2) ^ 2 + (z1 – z2) ^ 2)),  
(z1 – z2) / (sqrt ((x1 – x2) ^ 2 + (y1 – y2) ^ 2 + (z1 – z2) ^ 2))
(z1 – z2) / (sqrt ((x1 – x2) ^ 2 + (y1 – y2) ^ 2 + (z1 – z2) ^ 2))
];</code>
];</sqf>
</dd>
</dd>


</dl>
</dl>

Revision as of 21:23, 13 May 2022

Hover & click on the images for description

Description

Description:
Unit vector, equal to direction from vector1 to vector2. In other words this command produces normalised vector between given 2 points.
To get a non-normalised vector, use vectorDiff.
Groups:
Math - Vectors

Syntax

Syntax:
vector1 vectorFromTo vector2
Parameters:
vector1: Array - vector 3D or 2D (since Arma 3 logo black.png2.00, z coordinate is defaulted to 0)
vector2: Array - vector 3D or 2D (since Arma 3 logo black.png2.00, z coordinate is defaulted to 0)
Return Value:
Array

Examples

Example 1:
[1,2,3] vectorFromTo [4,5,6]; // is the same as vectorNormalized ([4,5,6] vectorDiff [1,2,3]);

Additional Information

See also:
vectorDiff vectorCrossProduct vectorDotProduct vectorCos vectorMagnitude vectorMagnitudeSqr vectorMultiply vectorDistance vectorDistanceSqr vectorDir vectorUp setVectorDir setVectorUp setVectorDirAndUp vectorNormalized matrixMultiply matrixTranspose

Notes

Report bugs on the Feedback Tracker and/or discuss them on the Arma Discord or on the Forums.
Only post proven facts here! Add Note
Posted on 19 Jul, 2014
ffur2007slx2_5
Arma 3 logo black.png1.26 Algorithm:
Vector1 = [x1,y1,z1]; Vector2 = [x2,y2,z2]; Result = [ (x1 x2) / (sqrt ((x1 x2) ^ 2 + (y1 y2) ^ 2 + (z1 z2) ^ 2)), (y1 y2) / (sqrt ((x1 x2) ^ 2 + (y1 y2) ^ 2 + (z1 z2) ^ 2)), (z1 z2) / (sqrt ((x1 x2) ^ 2 + (y1 y2) ^ 2 + (z1 z2) ^ 2)) ];