forEach

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Description

Description:

Executes the given command(s) on every item of an array.
The array items are represented by the magic variable _x. The array indices are represented by _forEachIndex.
In Arma 2 and later, the variable _x is always local to the forEach block so it is safe to nest them.

Groups:

Uncategorised

Syntax

Syntax:

code forEach array

Parameters:

code:

• String (Operation Flashpoint / Arma)
• Code (Arma and later)

array: Array - the array to iterate

Return Value:

Anything - will return the value of last executed statement

Examples

Example 1:

// SQF { _x setDamage 1 } forEach units group player; ; SQS "_x setDammage 1" forEach units group player

Example 2:

This command can also easily be used to execute a single command multiple times without respect to the array items. { player addMagazine "30Rnd_556x45_Stanag"; } forEach [1, 2, 3, 4];

Example 3:

You can also use multiple commands in the same block: { _x setCaptive true; removeAllWeapons _x; doStop _x; } forEach units group this;

Example 4:

To get the index of a forEach loop, use _forEachIndex: { systemChat format ["%1", _forEachIndex]; } forEach [1,2,3]; // will return: "0", "1", "2" in systemChat messages

Additional Information

See also:

setresizepushBackpushBackUniqueapplyreverseselectinfindfindIftoArraytoStringcountdeleteAtdeleteRangeappendsortparamparamsarrayIntersectControl StructuressplitStringjoinString

Notes

Report bugs on the Feedback Tracker and/or discuss them on the Arma Discord.
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Notes

Posted on July 20, 2010

Kronzky

If arrays are used in forEach loops, _x uses them by reference, so any changes to _x will be applied to the original: _arr1 = [1,2,3]; _arr2 = [6,7,8]; { _x set [1,"x"] } forEach [_arr1,_arr2]; will change _arr1 to [1,"x",3], and _arr2 to [6,"x",8].

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Posted on August 29, 2014 - 22:23 (UTC)

Fett Li

forEach returns any (the last passed value will be the return value or just Nothing, depends on the function called). _var = {_x} forEach [ nil,"s",objNull,configFile ]; // return bin\config.bin _var = {_x setCaptive true} forEach allUnits; // return nothing

Posted on September 20, 2014

Mossarelli

Using the foreach loop, since there are no variable for the index like say the for-do loop, there is a variable that you can use to check the index of the foreach loop. { if (_forEachIndex == 1) then { // Copilot _x addUniform "U_B_Soldier_VR"; } else { // Adams [_x, "B_Soldier_TL_F"] call BIS_fnc_loadInventory; _x addUniform "U_B_Soldier_VR"; _x setIdentity "Bootcamp_B_Adams"; }; } forEach _crew; So when the array is past from _crew to the loop, index 1 (which is the second element) is the copilot of the "B_Heli_Light_01_F" and he will get "U_B_Soldier_VR" as a uniform. While the pilot which is index 0 (first element), will get the same uniform but will get the loadout of "B_Soldier_TL_F" and the identity of "Bootcamp_B_Adams".

Posted on January 2, 2015 - 22:35 (UTC)

Heeeere's Johnny!

Using exitWith inside a forEach loop will make forEach actually return something, namely whatever the exitWith returns: _result = { if(_x isEqualTo 3) exitWith {"Hello"} } forEach [1,2,3,4,5]; //_result = "Hello"

Posted on November 28, 2017 - 13:46 (UTC)

dedmen

Be careful when deleting (deleteAt) elements from an Array while you iterate over it.
_forEachIndex will not move to reflect your change.
The forEach code is doing the same as _forEachIndex = 0; while {_forEachIndex < count _array} do { (_array select _forEachIndex) call code; _forEachIndex = _forEachIndex + 1; } So if you delete your current element from the array the other elements will shift forward. Meaning you skip one element.
Example: _array = [1,2,3,4,5,6]; {_array deleteAt _forEachIndex} forEach _array; After the first iteration your Array will be [2,3,4,5,6] and the _forEachIndex will be 1.
So on next iteration you get the element at index 1 which will be 3. So you've just skipped the 2.
So in the end you will only iterate over 1,3 and 6.